0=3x^2-21x+104

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Solution for 0=3x^2-21x+104 equation: 



0=3x^2-21x+104

We move all terms to the left:

0-(3x^2-21x+104)=0

We add all the numbers together, and all the variables

-(3x^2-21x+104)=0

We get rid of parentheses

-3x^2+21x-104=0

a = -3; b = 21; c = -104;
Δ = b2-4ac
Δ = 212-4·(-3)·(-104)
Δ = -807
Delta is less than zero, so there is no solution for the equation

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